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AS 3600-2009 Clause 13.1.2.6

AS 3600-2009 Clause 13.1.2.6

(OP)
In clause 13.1.2.6, in the text "Where a bar ends in a standard hook complying with Clause 13.1.2.7, the tensile development length of that end of the bar, measured from the outside of the hook/cog, shall be taken as 0.5 Lsy.t or 0.5 L_st as applicable", I could not figure out what the "0.5 L_st as applicable" refers to. Since the bar ends in a standard hook/cog, shouldn't the bent portion of the bar contribute to one half of Lsy,t as pointed out by Warner et al (reinforced Concrete 3rd Edition, p.173) ?

RE: AS 3600-2009 Clause 13.1.2.6

0.5 Lsy.t and 0.5 Lst are the same concept, the length of a hook is half the straight development length. Use Lsy.t if you want the hook to develop the full yield strength (fsy) of the bar. Use Lst (13.1.2.4) if you only need to develop a portion of the yield strength.

RE: AS 3600-2009 Clause 13.1.2.6

(OP)
Thank you cooperDBM for your comment.

I wonder if this clause was written to make design easier by assuming that the straight portion (measured to the outside of the cog) contribution as 0.5L_st (assuming that a full yield strength is not required) and the cog portion contribution conservatively assumed to be 0.5 L_st even though the cog portion contribution is actually 0.5 Lsy,t (> 0.5 L_st).

If I am evaluating the anchorage capacity of a rebar (in an existing structure) with a standard cog having a horizontal anchored portion (measured to the outside of cog) of length x (where x < 0.5 Lsy,t), is my total anchored length = x + 0.5 Lsy,t or is it 2x ?

RE: AS 3600-2009 Clause 13.1.2.6

I would say that if x is less than 0.5 Lsy.t then x = 0.5 Lst. Therefore, from 13.1.2.4, the stress than can be developed at x, sigma_st = fsy (2 x) / Lsy.t. It's perhaps conservative but it's defensible with a literal reading of the code. The development length of a hook is empirical so I would tend to be literal with the reading.

As a check you can look at it the other way around. Say you only want to develop half the yield strength of the bar. That would make Lst = 0.5 Lsy.t. With your first interpretation that would mean that with a look x could be zero (the end of the cog) since the remainder of the hook would develop 0.5 Lsy.t.. That wouldn't seem unreasonable. Your second interpretation would give x = 0.25 Lsy.t.

RE: AS 3600-2009 Clause 13.1.2.6

look = hook

RE: AS 3600-2009 Clause 13.1.2.6

You can only use a development of greater than .5 if you increase the bend radius to 10db or greater (clause 13.1.2.5).

If you use the bend radius defined in the standard hook (13.1.2.7) .5 is the maximum capacity of the bar you can develop, not matter how long the leg is past the bend. This is to limit concrete crushing with the curve.

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