Law curve help
Law curve help
(OP)
If I want to create a helix that is of a fixed arc length, but can have the radius/diameter modified so basically the smaller the diameter, the more over lap there is after the first 360 degrees and as the diameter increases, then the over lap reduces, then how could I define this using expressions please? (anyone else smell a deformable worm drive clip?)
Cheers
Si
Cheers
Si
Best regards
Simon NX 7.5.4.4 MP8 and NX 8.5 (native) - TC 8 www.jcb.com





RE: Law curve help
Now define the number of turns like this: n=LH/sqrt((pi()*D)^2+pitch^2) where D is the helix diameter, pitch is the pitch (this is obvious) and LH is the length defined above. That's it.
You can note a subtle difference between the length calculated by NX and this one. If you unwrap the helix you can see the length is the same.
Regards
Frank.
RE: Law curve help
Not quite what I was looking for, I should have said that the helix is 2D and when viewed from above should not be a perfect circle, but and spiral which is gradually increasing in radius.
Best regards
Simon NX 7.5.4.4 MP8 and NX 8.5 (native) - TC 8 www.jcb.com
RE: Law curve help
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RE: Law curve help
www.nxjournaling.com
RE: Law curve help
RE: Law curve help
www.nxjournaling.com