Flattened Tube - Resulting Strength - Finite Element Analysis (FEA)
Flattened Tube - Resulting Strength - Finite Element Analysis (FEA)
(OP)
I am looking at flattening the end of a tube for an easier mechanical connection, but I want to make sure the resulting shape is strong enough to handle the applied design loads. I can make the part in Autodesk Inventor and run it through the program's FEA application, but with my limited knowledge of FEA, I am not 100% sure how to analyze the results.
From what I know, I should be looking at the Von Mises Stress, Safety Factor, and Displacement.
Von Mises: I am looking a these stresses and comparing them with the yield stresses of the material (in my case 50 KSI). So long as these stresses are less than the yield stresses, I am okay, correct?
Safety Factor: I am looking at these values to see how many times the applied force can be applied before it fails. I assume I want to keep this at 2 and above?
Displacement: The part should have minimal displacement, as determined by my system's requirements.
Are my assumptions correct? Is there anything else I need to be looking at?
Thanks,
Paul
From what I know, I should be looking at the Von Mises Stress, Safety Factor, and Displacement.
Von Mises: I am looking a these stresses and comparing them with the yield stresses of the material (in my case 50 KSI). So long as these stresses are less than the yield stresses, I am okay, correct?
Safety Factor: I am looking at these values to see how many times the applied force can be applied before it fails. I assume I want to keep this at 2 and above?
Displacement: The part should have minimal displacement, as determined by my system's requirements.
Are my assumptions correct? Is there anything else I need to be looking at?
Thanks,
Paul





RE: Flattened Tube - Resulting Strength - Finite Element Analysis (FEA)
I'm not having a go, I am pleased to see you ask the right sort of questions, I wish more engineers would. But they are a bit scary.
As ever more detail and drawings would be useful.
A typical design detail seen on children's swings is a crossbar for the basic triangle that is made from a tube (hence forming an A), flattened at each end, and then with a bolt through each end into the main tubes. The failure mechanisms are many, surprisingly few in my limited experience associated directly with the flattened bit of tube.
Cheers
Greg Locock
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RE: Flattened Tube - Resulting Strength - Finite Element Analysis (FEA)
Thanks for the response. I am just wondering about the flattened end, which will also be punched with a slot/hole for a bolted connection, designed to not be scary per AISC.
This is a part for a solar application that will have minimal risk to life. Attached is a drawing of the part (http://files.engineering.com/getfile.aspx?folder=8...). Please do not worry about the bracket at the top, or the foundation below.
Thanks in advance for any help!
RE: Flattened Tube - Resulting Strength - Finite Element Analysis (FEA)
RE: Flattened Tube - Resulting Strength - Finite Element Analysis (FEA)
With respect - you could be over-thinking this - flattened-end tubes are a perfectly common detail (and cheap - certainly cheaper than a welded gusset or similar!) for non-critical structural connections. (I would probably think twice about using this detail in critical aerospace or nuclear applications, but for a simple structural connection - no problem.)
@Hammer335i:
For a simple static application as yours seems to be, do you even need a detailed shell-element FEA? You could just analyse the members using beam elements with a pin at the flattened end. You can also model the flattened end using plate / shell elements if you need detailed stresses - treat the residual stresses from the flattening operation as part of the "member fabrication" process, similar to welding residual stresses, etc. The residual stresses won't really affect the ultimate static load capacity of the member.
http://julianh72.blogspot.com
RE: Flattened Tube - Resulting Strength - Finite Element Analysis (FEA)
Buckling strength, which your linear static FEA will not capture.
Applicable standards, which could place factors in front of loads or allowable stresses
tg