ASME VIII Div1 Appendix 24 ( clamp connection )
ASME VIII Div1 Appendix 24 ( clamp connection )
(OP)
Could you please help me to derive the M0, rotational moment equation provided in ASME code.
Mo=0.5*W*(C-G) / tan(theta+mue)
Note:-
I do understand that M=F*Distance (N-mtr)
so the load for single bolt = W/2 =0.5W (N) and (C-G) = the distance between the neutral axis to the inside clamp)
but tan(theta+mue) not making any sense to my lazy brain ...





RE: ASME VIII Div1 Appendix 24 ( clamp connection )
BTW C-G is two times the distance..., as C and G are diameters.
prex
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RE: ASME VIII Div1 Appendix 24 ( clamp connection )
thanks a lot for your help.
its in the section 24-5 of this attached document .
the formula (6) is the one which I am struggling to understand.
RE: ASME VIII Div1 Appendix 24 ( clamp connection )
prex
http://www.xcalcs.com : Online engineering calculations
http://www.megamag.it : Magnetic brakes and launchers for fun rides
http://www.levitans.com : Air bearing pads
RE: ASME VIII Div1 Appendix 24 ( clamp connection )
thanks for the informations.
Could you also let me know how the "MH" reaction moment at hub neck is worked out.
the main reason was when I use the ASME calculation the longitudinal stress "S1" is higher than the material yield strength.
So the two factors affecting this is due to the reaction moment & its rotational moment.
But my understanding is that the longitudinal stress is half of hoop stress. but in my calculation it seems that the longitudinal stress is much higher.
any thoughts on this .
once again thanks a lot for your help.