1-Phase Load, 3-Phase Supply
1-Phase Load, 3-Phase Supply
(OP)
How do you calculate the current on each line conductor for a resistive load?
The load is single phase, 575V Line-Line, 1000W Resistive
I = 1000W / 575V / 1.73 = 1.005A
or is it
I = 1000W / 575V = 1.739A because it's single phase?
Is it correct to call it a single phase load because it's only connected to 2 out of 3 phases at the supply?
The load is single phase, 575V Line-Line, 1000W Resistive
I = 1000W / 575V / 1.73 = 1.005A
or is it
I = 1000W / 575V = 1.739A because it's single phase?
Is it correct to call it a single phase load because it's only connected to 2 out of 3 phases at the supply?






RE: 1-Phase Load, 3-Phase Supply
RE: 1-Phase Load, 3-Phase Supply
Best to you,
Goober Dave
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RE: 1-Phase Load, 3-Phase Supply
Does it mean phase A will carry a load of I = 1000W / 575V = 1.739A * 2 = 3.478 amps
phase B & C will carry a load of I = 1000W / 575V = 1.739A = 1.739 amps
Thanks guys
RE: 1-Phase Load, 3-Phase Supply
RE: 1-Phase Load, 3-Phase Supply
IA = IBA - IAC vectorially
RE: 1-Phase Load, 3-Phase Supply
All phase currents have to sum to zero as usual, so IA = -IB - IC. But magnitude of phase B and C currents is as you describe - the load current of 1.739A.