Calculating how much moisture removal is required..
Calculating how much moisture removal is required..
(OP)
I am working on a project for a local 4H camp. They have dormitories where the kids sleep, up 50 per dorm, with a shared shower/toilet room. 4 showers and 4-5 toilets. Currently there is no exhaust at all (not sure how they got away with that, as the windows are not operable). The shower/toilet room is supplied from a split system DX unit, but no return. I am adding exhaust fans with CFM calculated by the code, but they also want to install a small dehumidification unit in each shower/toilet room. I am trying to come up with a calculation/formula that will tell me how many pints/day i need to remove. It varies, i know as to how many kids are showering, etc, but i just need a starting point.
Any one have any pointers?
Thanks!
Any one have any pointers?
Thanks!





RE: Calculating how much moisture removal is required..
I also notice you mention wanting to run a DX unit. From experience, DX units are not usually capable of sufficient de-humidification in water laden environments, such as gymnasiums and swimming pool areas and this typically requires a water based system.
RE: Calculating how much moisture removal is required..
and see for yourself. All the hotels with indoor pools have similar units.
RE: Calculating how much moisture removal is required..
In any case, with respect to following up on the question of sizing, the main thing that needs to be determined is the (latent) heat load of the room. Showers will act as atomizers putting a lot of water into the air at fairly warm temperatures. If you could get a set of readings, such as RH and dry bulb, or dry bulb and wet bulb temperatures that will give you a starting point for your calculation. You can then determine how much moisture you need to remove. For example, if the area is 95F dry bulb at 40% humidity, that gives you a ~100 grains of moisture per pound of air. If you are trying to condition the space down to 75F 50% humidity, you would need to reduce the moisture content to ~66 grains per pound of air. Of course if you are not cooling and just removing moisture, you need a lower relative humidity. All of this gets us into the realm of needing the size of the room, etc, to calculate the air volume, In any case, knowing the starting conditions and the target conditions, the supplier should be able to help you size a unit properly.
RE: Calculating how much moisture removal is required..
RE: Calculating how much moisture removal is required..