dead head pump
dead head pump
(OP)
how to calculate the output power of a dead head pump; since we donot have a flow at dead head condition and the head is maximum. I do have the input power which is close to 2.7KW.
what considerations of the loss should i take(is it the impeller losses and the motor losses along with the LRP)
sombody kindly help......
what considerations of the loss should i take(is it the impeller losses and the motor losses along with the LRP)
sombody kindly help......





RE: dead head pump
Ted
RE: dead head pump
http://www.engineeringtoolbox.com/pumping-water-ho...
Pwhp = q h sg / 3960 (1)
where
Pwhp = water horsepower (hp)
q = flow (gal/min)
h = head (ft)
sg = specific gravity
RE: dead head pump
l/s x h (metres)x sg (1 for H2O)/ 102 = kW.
However, the OP has asked for output power at CV which is a meaningless question as it is presented, the enquiry needs to be clarified.
It is a capital mistake to theorise before one has data. Insensibly one begins to twist facts to suit theories, instead of theories to suit facts. (Sherlock Holmes - A Scandal in Bohemia.)
RE: dead head pump
Power in put will be converted into heat energy but not all the 2.7kw of electrical power to the motor.
Need to minus the losses in the motor and mechanical looses in the pump bearings.