Calculate the force exerted on a floor (unit issue)
Calculate the force exerted on a floor (unit issue)
(OP)
I am trying to calculate the pressure a machine exerts on a floor. My 3D cad reports the mass as 10,000 lbmass. The area of all the feet is 100 inches square. The floor mfg. reports the maximum allowable is 3,000 psi. Assume the load is evenly distributed over the feet.
Is the pressure exerted 10,000 lbmass / 100 inches square = 100 psi
Or do I need to multiply the 10,000 lbmass by 32.2 ft/sec^2 to get pounds force. Therefore 10,000 lbmass (32) / 100 inches square = 3,200 psi.
Is the pressure exerted 10,000 lbmass / 100 inches square = 100 psi
Or do I need to multiply the 10,000 lbmass by 32.2 ft/sec^2 to get pounds force. Therefore 10,000 lbmass (32) / 100 inches square = 3,200 psi.





RE: Calculate the force exerted on a floor (unit issue)
RE: Calculate the force exerted on a floor (unit issue)
Ted
RE: Calculate the force exerted on a floor (unit issue)
Regards,
Cockroach
RE: Calculate the force exerted on a floor (unit issue)
Tobalcane
"If you avoid failure, you also avoid success."
“Luck is where preparation meets opportunity”
"People get promoted when they provide value and when they build great relationships"
RE: Calculate the force exerted on a floor (unit issue)
lbf = lbm * g / gc
N = kg * g / gc
In the first case g and gc happen to be numerically equal.
In SI gc happens to be 1, but it's still there, if only implied.
Neither is more complicated/correct/whatever than the other.
Slugs seem to be an anachronism in my experience. Never see the buggers.
RE: Calculate the force exerted on a floor (unit issue)
I also don't suscribe to your interpretation of "gravitational constant", you fail to reference the curvature of space-time as a continuum. Your statements are awfully Newtonian in nature. This would be important in terms of the general relativistic theory, the special counterpart refers to bodies approaching that velocity in the vicinity of light and the tensors generated in the mathematics thereof. Again, I further assume DPMechEng is not entering regions of increasing continuum curvature, frequency shifting due to gravity becoming important.
Just saying....but I digress....
Regards,
Cockroach
RE: Calculate the force exerted on a floor (unit issue)
RE: Calculate the force exerted on a floor (unit issue)
F=Lbf
m=Lbm
a=ft/sec^2
gc=32.2 bm-ft/lbf-sec^2
RE: Calculate the force exerted on a floor (unit issue)
RE: Calculate the force exerted on a floor (unit issue)
Tobalcane
"If you avoid failure, you also avoid success."
“Luck is where preparation meets opportunity”
"People get promoted when they provide value and when they build great relationships"