Shear induced Tension in concrete design
Shear induced Tension in concrete design
(OP)
Hi there,
I've been looking around for information about this topic, but can't seem to find much. The problem I'm currently having is that I'm verifying the capacity of an existing concrete structure to see if it can be used for storage (7.2 kPa, 150 psf), and many provisions regarding shear induced tension were not in place when the building was built. As such, nothing in 11.3.9 in the A23.3-04 standard is satisfied at the supports, mostly because the bottom steel isn't properly developed.
In clause 11.3.9.5 it says that in the formula (Vf - 0.5Vs - Vp) * cot (theta), Vs cannot be higher than Vf. However, I've been told that the Vs that should be used in the formula is the portion that the steel will resist - or rather the portion that the concrete cannot resist - and should be calculated as Vs = Vf - Vc.
Can I really use Vs = Vf? Any input on this topic would be greatly appreciated.
Thank you for your time.
I've been looking around for information about this topic, but can't seem to find much. The problem I'm currently having is that I'm verifying the capacity of an existing concrete structure to see if it can be used for storage (7.2 kPa, 150 psf), and many provisions regarding shear induced tension were not in place when the building was built. As such, nothing in 11.3.9 in the A23.3-04 standard is satisfied at the supports, mostly because the bottom steel isn't properly developed.
In clause 11.3.9.5 it says that in the formula (Vf - 0.5Vs - Vp) * cot (theta), Vs cannot be higher than Vf. However, I've been told that the Vs that should be used in the formula is the portion that the steel will resist - or rather the portion that the concrete cannot resist - and should be calculated as Vs = Vf - Vc.
Can I really use Vs = Vf? Any input on this topic would be greatly appreciated.
Thank you for your time.






RE: Shear induced Tension in concrete design
RE: Shear induced Tension in concrete design
RE: Shear induced Tension in concrete design
RE: Shear induced Tension in concrete design
You cannot us Vs = Vf unless you have enough shear reinforcement, which would be unusual in most beams.
At the supports of simple spans and at the exterior supports of continuous spans, the flexural tension reinforcement must be capable of resisting a tensile force of Vf - 0.5Vs at the inside edge of the bearing area where Vs is the value based on the stirrups at that location.
BA
RE: Shear induced Tension in concrete design
The definition of Vs is stated very clearly in the code.