Oil Cooling System Help
Oil Cooling System Help
(OP)
I am an intern and have a project that I'm supposed to go look at. I would like to get some help on here first that way I don't sound like a dumb a$$ when I talk to my boss haha. The information I have is very limited and it is as follows.
they want to cool the oil from 180F to 60F in 2 hours. they are going to run a cooling medium through plates in the oil tank for the heat removal.... that is all the info i have.
What information do I still need and more importantly what equations and design steps will help me solve this problem.
Appreciate all the help in advance.
they want to cool the oil from 180F to 60F in 2 hours. they are going to run a cooling medium through plates in the oil tank for the heat removal.... that is all the info i have.
What information do I still need and more importantly what equations and design steps will help me solve this problem.
Appreciate all the help in advance.





RE: Oil Cooling System Help
Where:
Q = BTU/hour of heat transferred.
M = pounds, or lb.
Cp = specific heat at constant pressure = BTU/lb/degree F
delta T = change in fluid temperature = (180 - 60) degrees F = 120 deg F.
You say "oil." There are many different "oils", so let's just guess that the Cp of your oil is 0.43 BTU/lb/degree F. You don't say how many pounds (or gallons) are in the tank, so we can calculate what happens for one (1) gallon, assuming 7.5 lb/gallon density.
Q = [M x Cp x delta T] / [2 hours]
Q/gallon = [1 gal) x 7.5 lb/gal] x [0.43 BTU/lb/deg F] x [120 deg F] / [2 hours]
Q/gallon = 193.5 BTU/hour/gallon.
If your tank has 8,000 gallons of oil, your heat transfer is:
8,000 gal x 193.5 BTU/hr/gal = 1,548,000 BTU/hour.
Hope this helps.
RE: Oil Cooling System Help