Sprinkler & Standpipe Hydraulic Calculation
Sprinkler & Standpipe Hydraulic Calculation
(OP)
Hi,
Hope you can help me on this.
As per NFPA 13, the most distant is not necessarily the HYDRAULICALLY most remote.
How do we identify the most hydraulically remote if not the most distant?
Appreciate any feedbacks.
Regards,
Jeff
Hope you can help me on this.
As per NFPA 13, the most distant is not necessarily the HYDRAULICALLY most remote.
How do we identify the most hydraulically remote if not the most distant?
Appreciate any feedbacks.
Regards,
Jeff





RE: Sprinkler & Standpipe Hydraulic Calculation
If you have an Ordinary hazard area in an otherwise light hazard building, and the OH area is not the most physically remote, you may have to calculate both to prove your pipe sizing.
With current calculation programs and drawing packages, calculations can be completed relatively quickly, so it is crazy not to run additional "proof" calculations if there is any concern as to what is the most demanding area.
Travis Mack
MFP Design, LLC
www.mfpdesign.com
RE: Sprinkler & Standpipe Hydraulic Calculation
Consider the following: I've seen NFPA 13 residential plans where designers calculate the manufacturer's 1,000 sq. ft. for concealed space sprinklers yet they did not do a four head calc which was actually more demanding since they were utilizing 400 sq. ft. spacing. One area consisted of the 12 upright sprinklers, the other four pendants. But a simple hand calc with a calculator would have shown that the four sprinklers were more demanding when you consider four sprinklers flowing 40 gpm each (.10 X 400 sq. ft) equals 160 gpm on ONE line. That's a lot of friction loss for one line in a residential design. By comparison the concealed space uprights were flowing roughly 130 gpm but it was distributed over 3 lines, each line getting roughly 43.2 gpm (.10 X 144 sq. ft. = 14.4 gpm x 3 sprinklers = 43.2).
The calculator is your friend.
RE: Sprinkler & Standpipe Hydraulic Calculation
Appreciate it...
one more thing... looks like there is a problem on this:
1. ordinary hazard
2. area of sprinkler - 139m2
3. density - 6.1 LPM (0.15gpm/ft2)
4.no. of sprinkler calculated - 13nos
5. max coverage per sprinkler - 12.1m2
6. total discharge through sprinkler - 1,034.1 LPM
Question:
Item 4 : should be 12nos and not 13nos (=139/12.1)
Item 6 : should be 885.72 LPM and not 1,034.1 LPM (=6.1x12.1x12)
Am I correct?
Thanks.