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mhpatel (Chemical)
20 Jul 12 16:31
Hi
Please help. I want to calculate how much steam required to evaporate 27,000 kg/hr water.
Feed: 60% Water, 40% CaCl2
flowrate: 70,000 lb/hr

Product: 40% Water, 60% CaCl2
Steam condition: 23 Barg steam

Thank you
TD2K (Chemical)
20 Jul 12 16:59
I think you'll have more than 60% CaCl2 if you evaporate 27,000 kg/hr of water out of a feed stream of 70,000 lb/hr.

DOW has a nice handbook on CaCl2 that you can download off the Internet. That and your steam tables should give you what you need.
HEC (Mechanical)
23 Jul 12 2:59
Just love the mixed units, imperial and metric. A minor point but what is hte feed temperature and expected outlet temperature of the mixture?

Mark Hutton


mhpatel (Chemical)
23 Jul 12 11:14
Thanks,
sorry water removal rate is 27,000 lb/hr.
Feed temperature is 45 C. The outlet temperature is not fix.

Regards,
Madan Patel

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