acetone latent heat at reduced pressure
acetone latent heat at reduced pressure
(OP)
Dear All
I wanted to know the latent heat of vaporization of acetone at 680mmHg for my condenser design, but could not find it. as latent heat decreases with increase in pressure and vice versa.
would somebody refer to some source or provide related equation.
Thanks
Saleda
I wanted to know the latent heat of vaporization of acetone at 680mmHg for my condenser design, but could not find it. as latent heat decreases with increase in pressure and vice versa.
would somebody refer to some source or provide related equation.
Thanks
Saleda





RE: acetone latent heat at reduced pressure
You can use the equation below:
ln p = - ΔHvap/RT + C
where
p is the vapour pressure
ΔHvap is the heat of vaporization
R is the gas constant (8.314 J/mole K)
T is the equilibrium temperature at vapour pressure p
C is a constant of integration
You can use known value of ΔHvap (at given vapour pressure and saturation temperature) to calculate C. Then, considering that at 680 mmHg the saturation pressure is 348.67 K, you can find ΔHvap at your conditions.
RE: acetone latent heat at reduced pressure
Watson correlation on page 3
Good luck,
Latexman
RE: acetone latent heat at reduced pressure
p = 680 mmHg
T = 326.2 K
it should be
ΔHvap = 29488 J/mol
RE: acetone latent heat at reduced pressure
Your result shows lower Hvap value than at ATM pressure. whereas it should increse.
My calculation results 125.82 cal/gm at 680 mmHg than 124.3 cal/gm at ATM.
Plz validate.
Thanks,
Saleda
RE: acetone latent heat at reduced pressure
log Psat = A - B/(T+C)
P in torr, T in oC
A=7.11714
B =1210.595
C = 229.664
Range of applicability: from -13 to +55oC.
RE: acetone latent heat at reduced pressure
at p = 760 mmHg and T = 329.4 K, the enthalpy of vaporization ΔHvap is approx 29281 J/mol, while at p =680 mmHg and T = 326.2 K ΔHvap is 29488 J/mol.
You might want to check at webbook Nist
http://webbook.nist.gov/cgi/cbook.cgi?ID=C67641&Mask=4&Type=HVAP-FORM2&Plot=on#HVAP-FORM2