Hand Wheel Rim Pull Calculation
Hand Wheel Rim Pull Calculation
(OP)
Does anyone know how to calculate hand wheel rim pull on a worm gear system?
The gear box turns as follow:
Hand Wheel -> Worm -> Worm Gear -> Acme Threaded Shaft ->
How can I determine the rim pull force required to attain a certain linear force at the end of the system? See a drawing of the system here: http://www.freeimagehosting.net/mkp9q.
Questions are welcomed. Thanks!
The gear box turns as follow:
Hand Wheel -> Worm -> Worm Gear -> Acme Threaded Shaft ->
How can I determine the rim pull force required to attain a certain linear force at the end of the system? See a drawing of the system here: http://www.freeimagehosting.net/mkp9q.
Questions are welcomed. Thanks!





RE: Hand Wheel Rim Pull Calculation
Regards,
Cockroach
RE: Hand Wheel Rim Pull Calculation
Unless I am missing something, this looks like very basic machine design stuff. Torque into the worm equals force times radius. Torque out of the worm gear is multiplied by the ratio, and you subtract significant amounts of friction. The acme thread is similar. You have not provided details.
This is a simple problem for an engineer or an engineering technologist. What is your background?
RE: Hand Wheel Rim Pull Calculation
RE: Hand Wheel Rim Pull Calculation
Yes I took machine design.
RE: Hand Wheel Rim Pull Calculation
rmw
RE: Hand Wheel Rim Pull Calculation
Lots of small gear-motors are capable of self destruction, without hand-wheels.