SHELL MESHING DOUBTS
SHELL MESHING DOUBTS
(OP)
Why do we use quad and trias in shell meshing for automotive analysis? why not other 2-D elements?
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS Come Join Us!Are you an
Engineering professional? Join Eng-Tips Forums!
*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail. Posting GuidelinesJobs |
|
RE: SHELL MESHING DOUBTS
there is a tiny population of non-quad elements, used for transition. but you can mesh any surface with tris (remember tri3s "suck", tri6s are much better) and most surfaces with quads (the fourth node on the quad can create warped elements, but if this isn't excessive it isn't a problem).
RE: SHELL MESHING DOUBTS
RE: SHELL MESHING DOUBTS
Why stop at pentagons? Why not heptagons, octagons, dodecagons, tetradecagons, heptadecagons, ...
In the absence of pentagonal and hexagonal elements etc, I guess you will just have to mesh with TRIs and QUADs. You can make a pentagon out of 5 triangles (or if you don't want to generate an extra internal node, try three triangles, or one quad and a triangle), while there are several ways to make a hexagonal "element" (such as 6 triangles, one quad and two triangles, two quads and two triangles, ...)
http://julianh72.blogspot.com
RE: SHELL MESHING DOUBTS
why a pentagon ? it's harder to have 5 points on a plane than 4.
of course you could code for yourself a generally spherical 5 noded pentagon element
RE: SHELL MESHING DOUBTS
This is the direct link to the manual:
http://w
RE: SHELL MESHING DOUBTS
I am stretching my logical reasoning capability here. So I might be wrong.
The reason i think is because of the node count. If you refer back to the theory of FEA, you end up solving matrices for an element of 2 nodes (that is the starting point FEA theory that everyone studied I guess). While doing so, we combine matrices for both the nodes and endup with a bigger matrix. This should mean the higher the number of nodes, the bigger is our stiffness matrix and hence more complications and solution time.
Keeping that in mind, the least number of nodes that we can use in 2D is 3. But, tria's are not recommended for analysis for well known reasons. So the next available option is quad (4 nodes).
to all: Please feel free to correct me if I am wrong. I wrote this by combining everything I have learnt (which is just a drop in ocean)in FEA.
- This is me
RE: SHELL MESHING DOUBTS
i don't think so. a model of 4 5-noded 2d shells would have the same number of freedoms as 5 4-noded shells ... how they relate to one another would (of course) be different.
RE: SHELL MESHING DOUBTS