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Question about C=0 Zero Acceptance Number Sampling Plan

Question about C=0 Zero Acceptance Number Sampling Plan

Question about C=0 Zero Acceptance Number Sampling Plan

(OP)

My company is using the following sampling table based on Nicholas Sequigla's Zero Acceptance Number Sampling Plan:

http://guidebook.dcma.mil/226/tools_links_file/stat-sample.htm

My question is where do the sampling size numbers in the table come from?  What statistics equation/formula is used to arrive at these sampling size numbers?  How is this statistics formula used to get these numbers?  

I have read that the numbers may come from Hypergeometric distribution, Poisson distribution, or Binomial distribution.  I have tried applying these formulas but still do not understand how they got the numbers in the table.

For example, the table states that for a lot size of 51 to 90 and AQL of 1%, the sample size is 13.  My question is how was it determined that 13 is the sufficient sample size?  There must be a statistics formula used to calculate this 13.

If someone can proivde me with a thorough explanation, I would truly appreciate it.

RE: Question about C=0 Zero Acceptance Number Sampling Plan

(OP)
I have come across this book during my research on this topic over the internet.  Do you have a copy of this book and does it explain how the numbers in the table are calculated?

RE: Question about C=0 Zero Acceptance Number Sampling Plan

The probability of acceptance and associated AQL level (or index) are based on operating characteristic (OC) curves generated using a hypergeometric distribution allowing for no defects for a given lot and sample size. Googling "hypergeometric" and "sampling" should provide more information on generating the OC curve. For example, http://mathdl.maa.org/mathDL/4/?pa=content&;sa=viewDocument&;nodeId=428&pf=1.

If you are using the c=0 sampling plan, then you really should have buy Squeglia's book to cross reference.

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