Shell Elements Assembly - VALUABLE QUESTION
Shell Elements Assembly - VALUABLE QUESTION
(OP)
Dear readers,
I will make the long story short, so consider the sample shell geometry shown: ( 3 x 4 elements - 4 nodes/element)
4-------8--------12-------16--------20
| | | | |
3-------7--------11-------15--------19
| | | | |
2-------6--------10-------14--------18
| | | | |
1-------5---------9-------13--------17
if the horizontal is the tangential direction (r*theta)and the vertical is the axial direction (so you see a top view here). How do you assemble a circular shell?
My answer is that the right end nodes have to take the same numbers as the left end nodes (to form a closed circle). Thus,
4-------8--------12-------16--------4
| | | | |
3-------7--------11-------15--------3
| | | | |
2-------6--------10-------14--------2
| | | | |
1-------5---------9-------13--------1
and the integration limits for an element in the circumferential direction is 2*pi/4, such that each elements has an angle of pi/2, and the 4 elements will form 2*pi to close the circle.
Any thing wrong with what I mentioned here? Please make sure that you know the right answer before replying.
Thanks for your time!
I will make the long story short, so consider the sample shell geometry shown: ( 3 x 4 elements - 4 nodes/element)
4-------8--------12-------16--------20
| | | | |
3-------7--------11-------15--------19
| | | | |
2-------6--------10-------14--------18
| | | | |
1-------5---------9-------13--------17
if the horizontal is the tangential direction (r*theta)and the vertical is the axial direction (so you see a top view here). How do you assemble a circular shell?
My answer is that the right end nodes have to take the same numbers as the left end nodes (to form a closed circle). Thus,
4-------8--------12-------16--------4
| | | | |
3-------7--------11-------15--------3
| | | | |
2-------6--------10-------14--------2
| | | | |
1-------5---------9-------13--------1
and the integration limits for an element in the circumferential direction is 2*pi/4, such that each elements has an angle of pi/2, and the 4 elements will form 2*pi to close the circle.
Any thing wrong with what I mentioned here? Please make sure that you know the right answer before replying.
Thanks for your time!





RE: Shell Elements Assembly - VALUABLE QUESTION
RE: Shell Elements Assembly - VALUABLE QUESTION
RE: Shell Elements Assembly - VALUABLE QUESTION
RE: Shell Elements Assembly - VALUABLE QUESTION
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RE: Shell Elements Assembly - VALUABLE QUESTION
RE: Shell Elements Assembly - VALUABLE QUESTION
of course, if the elements form a closed loop then the last set of nodes numbers is the same as the first. if you don't use the same nodes then the loop isn't closed (even if the nodes are coincident).