Lighting: Calculating Efficacy with power factor
Lighting: Calculating Efficacy with power factor
(OP)
Hi, Im trying to calculate efficacy for a lighting assignment, I know the equation for efficacy is Lumens divided by Power but this question includes a power factor rating, how do I incorporate this into the equation?? would i need to multiply Power (Watts) by power factor??






RE: Lighting: Calculating Efficacy with power factor
You have to account for the ballast losses. This should be provided with the ballast data.
David Castor
www.cvoes.com
RE: Lighting: Calculating Efficacy with power factor
RE: Lighting: Calculating Efficacy with power factor
RE: Lighting: Calculating Efficacy with power factor
David Castor
www.cvoes.com
RE: Lighting: Calculating Efficacy with power factor
"Dear future generations: Please accept our apologies. We were rolling drunk on petroleum."
— Kilgore Trout (via Kurt Vonnegut)
For the best use of Eng-Tips, please click here -> FAQ731-376: Eng-Tips.com Forum Policies
RE: Lighting: Calculating Efficacy with power factor
In your case, it would only make a 2% difference anyway.
RE: Lighting: Calculating Efficacy with power factor
David Castor
www.cvoes.com
RE: Lighting: Calculating Efficacy with power factor
RE: Lighting: Calculating Efficacy with power factor
"Dear future generations: Please accept our apologies. We were rolling drunk on petroleum."
— Kilgore Trout (via Kurt Vonnegut)
For the best use of Eng-Tips, please click here -> FAQ731-376: Eng-Tips.com Forum Policies
RE: Lighting: Calculating Efficacy with power factor
I could see you using the lamp watts and the ballast efficiency to calculate incoming watts and then use the power factor to calculate incoming VA to know how much current the light will draw.
You really don't seem to know what you want here. Maybe you should take a step back and figure out what numbers you need and why you need them.