equivalent impedance of cables in parallel
equivalent impedance of cables in parallel
(OP)
we have 3 cables 4/0 AWG to calculate the equivalent impedance in parallel. Assuming current flow equal to three cables would have:
Req = R / 3 and Xeq = X / 3
Considering that in reality never has a distribution of current flow equal to 3 cables asks:
Is there a correction factor for the uneven distribution of current to be included in the calculation?
Req = R / 3 and Xeq = X / 3
Considering that in reality never has a distribution of current flow equal to 3 cables asks:
Is there a correction factor for the uneven distribution of current to be included in the calculation?






RE: equivalent impedance of cables in parallel
Cable impedances are always an approximation.
Also, if you are just trying to calculate the fault current, assuming equal impedances should give acceptable results.
David Castor
www.cvoes.com
RE: equivalent impedance of cables in parallel
Resistance of the cable is more or less constant for the given temperature.
RE: equivalent impedance of cables in parallel
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page 8/20.