Measuring Pressure Drop
Measuring Pressure Drop
(OP)
I am wondering about measuring the pressure drop of a piping system. Right now we are using two piezometer rings, one before the object for which I want to measure the pressure drop and one after. Therefore, I am measuring static pressure before and after the object and calculating the pressure drop by subtracting the two values.
It is bothering me that we are not taking the velocity head into account. Are our measurement method and calculation valid? Why or why not? Can you point me to a reference?
Thank you for your time.
It is bothering me that we are not taking the velocity head into account. Are our measurement method and calculation valid? Why or why not? Can you point me to a reference?
Thank you for your time.





RE: Measuring Pressure Drop
The value you are reading is total pressure so you're not leaving anything out, but if you were, then the error would cancel since you'd be leaving out of both instruments.
David
RE: Measuring Pressure Drop
RE: Measuring Pressure Drop
David
RE: Measuring Pressure Drop
Good luck,
Latexman
RE: Measuring Pressure Drop
RE: Measuring Pressure Drop
RE: Measuring Pressure Drop
RE: Measuring Pressure Drop
RE: Measuring Pressure Drop
Engrkatie, if velocity before and after your device remains essentially the same, ((V1-V2)^2)/2/g is so small you can neglect it, you wouldn't necessarily have to measure the velocity head too. If there is a significant change in velocity, you should add the velocity head to the static head to get the total.
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