MOMENT DESTRIBUTION METHOD FOR SIMPLE FRAME
MOMENT DESTRIBUTION METHOD FOR SIMPLE FRAME
(OP)
HELLO ALL: It has been over 30 years since I have worked witn the moment distribution . I am really rusty. By the way this is not a homework problem this is a real world problem. Here is the problem I am trying to solve.
A simple 2 dimensional frame with 8" legs and an 11 inch top cross piece. Both legs are anchored so they carry a moment, shear and axial loads. The crosspiece on the top is 11 inches long and has a 1000 pound load 5 inches from the left end. The technical information is:
material: steel - E=30,000,000 #/sq in
Moment of inertia - each 8" leg - .0088 in^4
Moment of inertia - crosspiece - .019 in^4
I have referred to Roark for a solution and a 1928 Structural Book I have. Neither seemed to work. I would like to go back to basics. Although the Moment Distribution Method yields only moments I will draw free body'd of each member to obtain shear and axial forces.
I would like to see the step by step solution. I will send my E-mail address for a copy of the solution.
Cordially
Dave
A simple 2 dimensional frame with 8" legs and an 11 inch top cross piece. Both legs are anchored so they carry a moment, shear and axial loads. The crosspiece on the top is 11 inches long and has a 1000 pound load 5 inches from the left end. The technical information is:
material: steel - E=30,000,000 #/sq in
Moment of inertia - each 8" leg - .0088 in^4
Moment of inertia - crosspiece - .019 in^4
I have referred to Roark for a solution and a 1928 Structural Book I have. Neither seemed to work. I would like to go back to basics. Although the Moment Distribution Method yields only moments I will draw free body'd of each member to obtain shear and axial forces.
I would like to see the step by step solution. I will send my E-mail address for a copy of the solution.
Cordially
Dave






RE: MOMENT DESTRIBUTION METHOD FOR SIMPLE FRAME
RE: MOMENT DESTRIBUTION METHOD FOR SIMPLE FRAME
(1/12)*(2)*(.375^3) =.0088
This is part of a small bracket that fits on the front of a vehicle and I am trying to determine the loads and stresses involved.
Thank you again
Regards
Dave
RE: MOMENT DESTRIBUTION METHOD FOR SIMPLE FRAME
In any case, the moment distribution method is dependent upon relative stiffnesses instead of absolute stiffnesses.
I think that teaching or describing the Moment distribution method on a site like this is a bit much. Get a good structural analysis textbook and it should have the method and steps required. Or invest in a cheap 2D program. I believe there are some out there.
Good Luck!
RE: MOMENT DESTRIBUTION METHOD FOR SIMPLE FRAME
Regards
Dave
RE: MOMENT DESTRIBUTION METHOD FOR SIMPLE FRAME
Most of us do not have time to do others work... and don't want the liability...Sorry
The moment distribution method is quite easy to do and is well defined in any good structures book.
RE: MOMENT DESTRIBUTION METHOD FOR SIMPLE FRAME
RE: MOMENT DESTRIBUTION METHOD FOR SIMPLE FRAME
Mike McCann
MMC Engineering