How to measure the area of individual elements on a model?
How to measure the area of individual elements on a model?
(OP)
I have an analysed model in Abaqus. Is it possible to measure the area of each of the elements associated on the model?





RE: How to measure the area of individual elements on a model?
I have had the need to perform a similar operation and used python scripting to calculate the areas based on nodal reference locations (easy, since I was doing a 2-d problem with triangular elements).
I am sure you want the deformed areas though, which I stopped short of calculating. I do not know if ABAQUS stores the current nodal locations, or just the nodal displacements relative to reference configuration (someone please clarify).
A long about way would be to use scripting to calculate the current nodal locations (reference locations plus current displacement) and then use the current locations to compute the area of the element.
Hope this helps,
Chris
RE: How to measure the area of individual elements on a model?
RE: How to measure the area of individual elements on a model?
RE: How to measure the area of individual elements on a model?
RE: How to measure the area of individual elements on a model?
Chris
RE: How to measure the area of individual elements on a model?
Sorry I've taken so long to respond to this thread. What I'm exactly looking for is the area of an element on a face. So what I have is quadrilateral element shapes. Is there a way to measure the area of a quadrilateral on a face?
Even if I was able get the correct distances from 1 node to the next then I could use the four distances and the formula of:
Area = Square Root of{(s-a)(s-b)(s-c)(s-d) -1/4(ac+bd+pq)(ac+bd-pq)}
where a,b,c and d are the four sides of the quadrilateral with a and c and b and d as the opposite sides, p and q are diagonals, and s = (a+b+c+d)/2
Example;
If a quadrilateral has four sides a,b,c,d, where a is the opposite side of c, and b is the opposite side of d, and their lengths are:
a=30, b=31, c=22, d=28 and the two diagonals are: p=34 and q=43, then the area of this quadrilateral is:
calculate semiperimeter (s) = (a+b+c+d)/2= 111/2 = 55.5
area is:
square root of {(55.5-30)(55.5-31)(55.5-22)(55.5-28)-1/4(30*22+31*28+34*43)(30*22+31*28-34*43)}
= Square root of {(25.5*24.5*33.5*27.5) - 1/4(660+868 +1462)(660+868-1462)}
=square root of {575550.94 - 1/4(2990)(66)}
=square root of {575550.94 - 1/4(197340)}
=square root of{575550.94 - 49335)}
=square root of {526215.94}
=725.41
But as I have over 192 elements this will be very time consuming
RE: How to measure the area of individual elements on a model?
If I am understanding your problem correctly, you have a 3D problem in which you are using brick elements, but want to know the areas of elements on a particular face (perhaps on a surface) and therefore need to calculate the respective areas of of the element faces on this surface? --> Correct if wrong.
In this case, there is no easier way I can think of except to script this process in python using the algorithm you mentioned in your post. You would need a clever way of extracting the nodal connectivity for only the elements and , more importantly, for only the face you need.
If this was a 2D problem you could have extracted the areas as field output as mentioned above.
RE: How to measure the area of individual elements on a model?
Then I have a script that can take the co-ordinates in an ABAQUS model and import them into a CATIA model.Then I can use the distance tool to measure between the four quadrilateral nodes. Then I am using a basic area quadrilateral calculator found on the Internet:
http://www.land.net/calc_four.php
It's just this method is very very time consuming and I don't have much time to measure over 192 elements and use the calculator to calculate the area of each quad shape
RE: How to measure the area of individual elements on a model?
Thanks for your help. I have found a simpler method of calculating the total area of the face in CATIA then dividing it by the number of elements. There is a slight discrepancy but it is only by around 0.064 for each element face, which I use for discussion.