shear-friction in a concrete wall
shear-friction in a concrete wall
(OP)
I am designing a concrete basement wall to be backfilled without support at the top, acting as a plate simply supported at the bottom by a slab and at it's ends by perpendicular walls. Using RISA-3D to analyze a plate element model I find that I can reinforce for the maximum vertical and horizontal moments, but I'm concerned about the possibility of a shear failure at the plan corners. If I fix the cormers the negative moments become impractically large without much reduction in the positive moments, and in any case the corner rotation due to warping of the perpendicular walls would be impossible to predict. So I thought I would use some bars on the soil side at the corners to limit crack width and provide some degree of rotational restraint, but still reinforce mid-span for the simply supported condition. I can check shear-friction capacity using these soil side bars and the opposite side bars which will be extended around the corner. Question: is this really an appropriate use of shear-friction? Because I am not reinforcing for the maximum moment but allowing some rotation, does this negate the shear-friction model? Also, is there a way to account for dowel action of the inside face bars? Any comments would be greatly appreciated.






RE: shear-friction in a concrete wall
I would design the wall as fixed on three sides. Use a reference such as "Moments and Reactions for Rectangular Plates" from the U.S. Department of the Interior, Water Resources Technical Publication, Engineering Monograph No. 27. Unfortunatly this publication is out of print, but maybe someone in your office has a copy. I suspect Risa is giving you some kind of unrealistic loads at the discontinuity. Using the moments and reactions from the reference, bite the bullet and make the wall thick enough to carry the shear (using formula 11-3 of ACI 318) at the base and sides. Note that you can design for a distance of "d" away per section 11.1.3.1. I've designed a lot of these walls and shear usually controls the thickness.
RE: shear-friction in a concrete wall
RE: shear-friction in a concrete wall
Be sure to include lateral forces on the added walls as well.
As far as shear friction goes - I wouldn't use it in this case. Usually, we check for phi x Vc against the Qx Qy forces that RISA provides and ensure adequate thickness to resist the forces. ACI's Equation - Vc = 2 x SQRT (f'c) x b x d is quite conservative - especially with phi = 0.85.
RE: shear-friction in a concrete wall
JAE - the Q forces from RISA are extremely high at the top & bottom of the wall, dropping off to lelss than 1/2 within a foot at the top and reversing in less than a foot at the bottom. I don't believe they represent reality. Is there a reasonable way to redistribute them?
RE: shear-friction in a concrete wall
1. Model in RISA-3D using full thickness of the wall (i.e. you are using Igross).
2. Calculate the cracking moment of the wall section ( a one foot section) using the ACI equation Mcr = fr x Ig / y where fr = 7.5 x Sqrt(f'c) and y is half your wall thickness.
3. Run the model and look for elements that have values of (Mx + Mxy) or (My + Mxy) greater than your Mcr. If so, then this "portion" of the wall cracks and therefore - edit those specific elements to be thinner - thus modeling a cracked wall. The thinner thickness that you choose could simply be Icracked. Usually using about 0.15 x Ig will suffice but you can be more detailed if you want.
4. Re-run the model again - again search for elements which exceed Mcr and size them down.
5. Repeat step 4 until the model converges. Thus, you will acually see the progression of the cracking in the wall. For my pool, I followed this procedure and the resulting "crack" was exactly the crack that existed in the pool wall that prompted my study in the first place.
This will/should re-distribute your Q forces. Note that after thinning up some elements you will get strange results in those thin elements. This takes some interpretation but I think it will do what you need.