Pressure V's Temperature
Pressure V's Temperature
(OP)
I am somewhat out of my field here (Mining Electrical Eng) and am hopeful someone can take the time to assist a layman.
An explosion of methane in a flameproof enclosure relies on escaping gases to be cooled as they cross a flamepath in order not to ignite an external explosive atmosphere. Methane explosions generate (I am led to believe)approx 600kPa 1500 deg C and sufficient temp reduction occurs to drop the temp generated in that explosion to below 537 deg C. The lengths and gaps of flamepaths, relative to enclosure volume, are critical in achieving this
Is Temperature versus pressure, as calculated from the ideal gas equation applicable
An explosion of methane in a flameproof enclosure relies on escaping gases to be cooled as they cross a flamepath in order not to ignite an external explosive atmosphere. Methane explosions generate (I am led to believe)approx 600kPa 1500 deg C and sufficient temp reduction occurs to drop the temp generated in that explosion to below 537 deg C. The lengths and gaps of flamepaths, relative to enclosure volume, are critical in achieving this
Is Temperature versus pressure, as calculated from the ideal gas equation applicable





RE: Pressure V's Temperature
David
RE: Pressure V's Temperature
"transfer of fairly small-BTU mass of gas into a much larger mass of steel"
This is what initiated my question. It has been a long held belief in the mining industry that this is the basis of flameproofing. However, not all flamepaths are steel (or other metals). Many flamepaths are polycarbonate materials, eg Burnbrite Exd lights, which led me to the supposition that cooling by depressurisation may be the underlying principle.
Further comment appreciated.
Regards.. Rod
RE: Pressure V's Temperature
David
RE: Pressure V's Temperature