pressure drop due to obstruction in pipe
pressure drop due to obstruction in pipe
(OP)
LS,
If a small cylinder is placed in a pipe, what will be the pressure drop.
The force acting on the cylinder will be:
F=Cw*A*0,5*rho*v^2
Flows are turbulent (Re>10000).
Should I use an energy approach?
Thanks DYV
If a small cylinder is placed in a pipe, what will be the pressure drop.
The force acting on the cylinder will be:
F=Cw*A*0,5*rho*v^2
Flows are turbulent (Re>10000).
Should I use an energy approach?
Thanks DYV





RE: pressure drop due to obstruction in pipe
Good luck,
Latexman
RE: pressure drop due to obstruction in pipe
this has been discussed before:
thread378-236832: Losses through long annulus.
RE: pressure drop due to obstruction in pipe
Let your acquaintances be many, but your advisors one in a thousand' ... Book of Ecclesiasticus
RE: pressure drop due to obstruction in pipe
The flow is normal to the surface of the cylinder. The cylinder is fixed to the piping wall.
Piping is DN50, and the cylinder has a diameter of 20 mm and a length of 35 mm.
On the internet I found a picture of how the flow is around the cylinder in this existing situation.
Flow will be approx. 18 m3/h (is approx. 2,5 m/s) and the fluid is light viscous (estimated at 10 mPas), which makes flow turbulent.
Pressure drop is very low, but it needs to be quantified.
DYV
RE: pressure drop due to obstruction in pipe
Best regards
Morten
RE: pressure drop due to obstruction in pipe
It is a capital mistake to theorise before one has data. Insensibly one begins to twist facts to suit theories, instead of theories to suit facts. (Sherlock Holmes - A Scandal in Bohemia.)
RE: pressure drop due to obstruction in pipe
RE: pressure drop due to obstruction in pipe
RE: pressure drop due to obstruction in pipe