Pressure drop through annular ring
Pressure drop through annular ring
(OP)
Anyone have a formula for pressure drop through an annular ring. I have found very limited information on the web, but from what I've found the pressure drop is different than that of an orifice because there are two separate surfaces with the ring. Any advice would greatly be appreciated.





RE: Pressure drop through annular ring
Ted
RE: Pressure drop through annular ring
http://www.eng-tips.com/faqs.cfm?fid=1142
RE: Pressure drop through annular ring
http://
RE: Pressure drop through annular ring
Katmar Software
Engineering & Risk Analysis Software
http://katmarsoftware.com
RE: Pressure drop through annular ring
Units are Imperial: ft-lb-sec system
P1-P2 = W^2/(2*g*rho*K^2*A^2)
Reynolds number for annular orifices: Re = W*(D-d)/(A*mu*g)
Find K from a chart. See fig 5, page 39 in the attached link.
http://nt
A, flow area, ft^2
d, minor diameter, ft
D, major diameter, ft
g, 32.2 ft/sec^2
K, orifice coefficient
L, flow length, ft
P, pressure, lb/ft^2
V, fluid velocity, ft/sec
mu, absolute viscosity, lb sec/ft^2
W, flow rate, lb/sec
rho, density, lb/ft^3
Yes, it is an older book.
Ted
RE: Pressure drop through annular ring
RE: Pressure drop through annular ring
If so, 3 pages from R. Miller's Flow Measurement Engineering Handbook are attached.
RE: Pressure drop through annular ring
here's 1st page
RE: Pressure drop through annular ring