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planetary gear sizing based on required output

planetary gear sizing based on required output

planetary gear sizing based on required output

(OP)
Hi I have a question regarding sizing the gear for a specific range of output.

I have an application where I have a carriage bringing material through cutting heads and then returning on a linear actuator. I would like to use an inverter duty motor (say anywhere from .5HP to 2HP). I would like to use a blue max motor since I have been told they are very good. I have also been told that planetary gears are the way to go since they are extremely durable (I am looking at around 1000 cycles per day, every day).

Based on the force required to take the material through the cutting heads, I have calculated that I need the following range of output:

80 RPM with approx 9000 in lbs of torque (carrying the material through the cutters).

300 RPM at very low torque (it is the returning the empty carriage for the next cutting cycle).

7RPM with 9000 in lbs of torque minimum (this is a slow speed setting I would like to have)

All of this is based on a 5.5" pulley driving the carriage.

Is any of this possible?

RE: planetary gear sizing based on required output


The power need to turn a shaft 80 rpm with 9000 in-lbs of torque is 11.42 HP. Some motors can take momentary overloads but usually not 6 times overload. So it is not possible to do this with a 2 HP motor.

RE: planetary gear sizing based on required output

(OP)
Thank you PeteDB:

So as long as I have 15HP motor (Not cheap for inverter duty), then I can do what I need?

RE: planetary gear sizing based on required output

You have to talk to someone familiar with the torque-speed capabilities of the motor. Knowing this would help you determine if you need a gearbox in front of the motor and what ratio is required for the gearbox.

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