Deflection of Simple Beam With uniform load partially distributed
Deflection of Simple Beam With uniform load partially distributed
(OP)
Does anyone have a formula for Deflection of Simple Beam With uniform load partially distributed. All the references that I have ignores the deflection along th beam with this type of loading. There is an old post 2006 by an ME but no good answer. One option seemed to be to take the load as from one end to the end of the load and take the load from the end to the begining of the load and subtract it from the first deflection. I tried that and I got some negative number and I know that cannot be. Help!





RE: Deflection of Simple Beam With uniform load partially distributed
Take a look at this example on this web site page 28 example2 it calls it a patch load.
http://
desertfox
RE: Deflection of Simple Beam With uniform load partially distributed
http://w
Other cases are not too difficult to derive from the Euler Bernoulli beam model:
Shear V is integral of Force
Moment M is integral of V
Slope is integral of M divided by the constant E*I
Displacement is integral of slope.
Divide the beam into enough sections so that you have only discrete forces applied at boundary of each section or forces which are constant over the length of each section.
Use conditions of static equilibrium to solve the reaction forces at each support. Now your boundary conditions at the ends and between the sections provide enough info to solve the unknown integration constants. It is pretty easy to do with a computer algebra program like Maple (Maple's "Heaviside" function is the same the "singularity" function of MaCaulay's method).
=====================================
(2B)+(2B)' ?
RE: Deflection of Simple Beam With uniform load partially distributed
Kenneth J Hueston, PEng
Principal
Sturni-Hueston Engineering Inc
Edmonton, Alberta Canada
RE: Deflection of Simple Beam With uniform load partially distributed
h
RE: Deflection of Simple Beam With uniform load partially distributed
The method you used is correct. The answer was wrong because of a mistake you made in the application of the equations. Do not look at your original calculation and do it again.
Mike McCann
MMC Engineering
Motto: KISS
Motivation: Don't ask
RE: Deflection of Simple Beam With uniform load partially distributed
RE: Deflection of Simple Beam With uniform load partially distributed
prex
http://www.xcalcs.com : Online engineering calculations
http://www.megamag.it : Magnetic brakes and launchers for fun rides
http://www.levitans.com : Air bearing pads