Modulus of Elasticity calculation
Modulus of Elasticity calculation
(OP)
Dear All,
I need the Modulus of Elasticity for some calculation. I have some values, but I am in doubt if it can be calculated with the values. The values I have are:
Rm = 1580 MPa
Rp0.2 = 665 MPa
Elongation 55 %
These are the values of stainless steel 316L at -253°C. now I need the E-modulus. In another thread I found E=1580/0.002 but I am doubting if this is correct.
Can anyone help me in finding the right value or calculation method?
thanks in advance.
Robert
I need the Modulus of Elasticity for some calculation. I have some values, but I am in doubt if it can be calculated with the values. The values I have are:
Rm = 1580 MPa
Rp0.2 = 665 MPa
Elongation 55 %
These are the values of stainless steel 316L at -253°C. now I need the E-modulus. In another thread I found E=1580/0.002 but I am doubting if this is correct.
Can anyone help me in finding the right value or calculation method?
thanks in advance.
Robert





RE: Modulus of Elasticity calculation
The 2% offset formula you were given is for normal temperatures. Steel properties are affected by temperature, both low and high, so I doubt the formula holds for your conditions.
RE: Modulus of Elasticity calculation
193 x 103 MPa
RE: Modulus of Elasticity calculation
the values I have received from the stainless steel foundation and they put the source at ASM Specialty Handbook. So I assumend the data was OK.
Do you have any data on this or know where I should try? -253C is a far more then i need and requested, but apparently the only one they had. I need approx -50C, and then the E-module and the yield strength.
Hope you, or anyone else, can tell me where I could find this information.
Robert
RE: Modulus of Elasticity calculation
The value of the elastic modulus above is valid for service temperatures below ambient for 316L stainless steel. You can use the reported yield strength (0.2% offset) for room temperature down to -50 deg C for 316L stainless steel.
RE: Modulus of Elasticity calculation
Thanks for your quick reply! this is what i needed. I will use your information for my further research.
thanks again.
Robert