×
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS

Log In

Come Join Us!

Are you an
Engineering professional?
Join Eng-Tips Forums!
  • Talk With Other Members
  • Be Notified Of Responses
    To Your Posts
  • Keyword Search
  • One-Click Access To Your
    Favorite Forums
  • Automated Signatures
    On Your Posts
  • Best Of All, It's Free!
  • Students Click Here

*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Students Click Here

Jobs

kW per hour calculation
2

kW per hour calculation

kW per hour calculation

(OP)
I'm monitoring power consumption on an electrically heated furnace.  I'm logging the kW with a data logger.  The kW readings/samples are each second.  How do I estimate the kW usage per hour based on the readings of kW I get per second?  Do I add up all the kW in one hour period?

Thanks,

RE: kW per hour calculation

kW is a measure of the rate of energy use. kW/s or kW/h as the second time derivative would be a measure of some sort of energy use acceleration. I don't think that is what you are looking for.

Your logger is simply recording power samples kW. If you want to know the average rate of energy use over an hour, simply add the data and divide by the # of samples to get an answer in units of kW. If you want to know the energy used in that hour, multiply the average by one hour to get the energy used in kWh.



 

RE: kW per hour calculation

The KW logger is like a speedometer telling how fast you are going.  The Kilowatt-hours (KWH) is the odometer telling how far you traveled. Since the logger doesn't record the odometer readings at the begining and end of the hour, just add up the one second readings and find the average.  With one second readings you will be real close.

RE: kW per hour calculation

KW is how fast your filling your beer mug.  KW-HR is how full it is.  KVAR would be like beer sloshing back and forth but not changing total volume.   I don't think there is such a thing as KVAR-HR but if there were I'd like to think it has something to do with foam.

 

=====================================
Eng-tips forums: The best place on the web for engineering discussions.

RE: kW per hour calculation

Hi Pete;
KVARHr is a standard metering quantity.
The historical method of determining power factor and the resulting penalties has been a KWHr meter with the voltage coils phase shifted to register KVAR Hours.
At the end of the billing period the months KWHrs and the months KVARHrs would be used to calculate the average power factor for the month and the PF penalty.
Small phase shifting transformers were added to a standard three phase meter. The transformers shifted the voltage 90 degrees so that the meter would register KVARHrs.
Old school power factor correction consisted first, of determining how many KVARHrs of capacity were required to improve the average power factor to a few percent above the penalty cutoff. Usually around 92%.
Then we would look for large motors or banks of motors that ran continuously. Fans in a lumber kiln were a great location, because they typically ran 24/7 even f the mill was on a 40 hour work week. We would correct these motors to 100%, and some times add 50% or double the amount of capacity. We may measure the no-load current of the supply transformer and add the same capacity.
Then we would start looking for large motors to correct. The code prohibits over correcting if the capacitor current passes through the motor overload device. By connecting the capacitors ahead of the O/L heaters we could go 50% or 100% over correction. We would tally the expected monthly running hours of each motor time the KVARs of correction added.
You needed some familiarity with the plant and process to avoid over-voltages, but as the large over corrected motors came online there would be a number of smaller uncorrected motors coming online to absorb the surplus KVARs.
With experience and judgment we could eliminate the penalties without generating excess voltages.

Yours
Bill

Bill
--------------------
"Why not the best?"
Jimmy Carter

RE: kW per hour calculation

Thanks Bill. So when the waves (kva) exist over a period of time, they causes the foam (kva-hr). I knew the foam had to fit in somehow.  

=====================================
Eng-tips forums: The best place on the web for engineering discussions.

RE: kW per hour calculation

Darned. I blew my punchline.  Subsitute kvar amd kvar-hr for kva and kva-hr.  

=====================================
Eng-tips forums: The best place on the web for engineering discussions.

RE: kW per hour calculation

No Pete, the mug is the KVA, the foam is the KVAR. Lets ask Scotty. He hates this analogy. GRIN

Bill
--------------------
"Why not the best?"
Jimmy Carter

RE: kW per hour calculation

Imagine a sea of beer. And then a strong wind blowing at 45 degrees. That wind will create waves and foam.

Now, there's a tug boat struggling to bring a boat across the sea and, at the same time, with the captain struggling so that the crew doesn't drink the beer.

This situation gives rise to a few questions:

1. What, then, is the analogy between tug captain and the CEO of the utility company?

2. If the frequency is 50 Hz, would the beer be a lager or an ale type of beer?

3. Is the sea half full or half empty?

4. Considering the wind and the foam - when will the crew be half-drunk?

Gunnar Englund
www.gke.org
--------------------------------------
100 % recycled posting: Electrons, ideas, finger-tips have been used over and over again...

RE: kW per hour calculation

Than you Gunnar, for one of the most entertaining analogies that I have encountered. I have re-read the questions several times and they remain - - - - - -       questions.
In that regard this analogy stands the test of time. Grin

Bill
--------------------
"Why not the best?"
Jimmy Carter

RE: kW per hour calculation

It wasn't really meant for you, Bill. I think that Scotty will appreciate it more fully and am looking forward to his answer, once he has recovered.

Gunnar Englund
www.gke.org
--------------------------------------
100 % recycled posting: Electrons, ideas, finger-tips have been used over and over again...

RE: kW per hour calculation

The supertanker model has intuitive appeal at the transmission level.

The mug (approx 0.473176473 liter) is more representative at the distribution and consumption level, which seems more relevant for this thread imo.

=====================================
Eng-tips forums: The best place on the web for engineering discussions.

Red Flag This Post

Please let us know here why this post is inappropriate. Reasons such as off-topic, duplicates, flames, illegal, vulgar, or students posting their homework.

Red Flag Submitted

Thank you for helping keep Eng-Tips Forums free from inappropriate posts.
The Eng-Tips staff will check this out and take appropriate action.

Reply To This Thread

Posting in the Eng-Tips forums is a member-only feature.

Click Here to join Eng-Tips and talk with other members!


Resources