×
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS

Log In

Come Join Us!

Are you an
Engineering professional?
Join Eng-Tips Forums!
  • Talk With Other Members
  • Be Notified Of Responses
    To Your Posts
  • Keyword Search
  • One-Click Access To Your
    Favorite Forums
  • Automated Signatures
    On Your Posts
  • Best Of All, It's Free!
  • Students Click Here

*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Students Click Here

Jobs

Stoichiometric number for methanol synthesis

Stoichiometric number for methanol synthesis

Stoichiometric number for methanol synthesis

(OP)
I realised that the stoichiometric number of the syngas required for methanol synthesis is often defined as
(H2-CO2)/(CO+CO2), and preferably at 2. Please may I know how to arrive to this definition?

Thank you.  

RE: Stoichiometric number for methanol synthesis


I assume it is related to the stoichiometric molar balance in two parallel reactions of hydrogen with carbon oxides:

CO + 2 H2 => CH3OH

Stoichiometrically 2 moles of hydrogen react with 1 mole of CO to produce 1 mole of methanol.

The xs hydrogen from syngas (as obtained from methane reforming) is reacted with CO2. In this reaction 3 moles of hydrogen react with 1 mole of carbon dioxide to produce 1 mole of methanol and 1 mole of water.

CO2 + 3 H2 => CH3OH + H2O

Combining both reactions we see that 5 moles of hydrogen react with 1 mole of CO and 1 mole of CO2.

Therefore, moles of hydrogen less moles of CO, divided by the sum of the moles of both carbon oxides is 2. In practice this number is adjusted by addition of hydrogen or CO2 as needed.

 

Red Flag This Post

Please let us know here why this post is inappropriate. Reasons such as off-topic, duplicates, flames, illegal, vulgar, or students posting their homework.

Red Flag Submitted

Thank you for helping keep Eng-Tips Forums free from inappropriate posts.
The Eng-Tips staff will check this out and take appropriate action.

Reply To This Thread

Posting in the Eng-Tips forums is a member-only feature.

Click Here to join Eng-Tips and talk with other members!


Resources