how to calculate time to cool an insulated tank
how to calculate time to cool an insulated tank
(OP)
Can someone provide some light as to time required to cool an insulated tank that is under steady state.
Is there a formulae?
Is there a formulae?





RE: how to calculate time to cool an insulated tank
you calculate the amount of heat to be retracted from the medium (kJ) (from t1 to t2)
you define the max time to cool from t1 to t2
you calculate the heat retraction required
delta t and kJ result in kW
RE: how to calculate time to cool an insulated tank
RE: how to calculate time to cool an insulated tank
RE: how to calculate time to cool an insulated tank
To me, it is similar to 'how long should I wait for a glass of hot water to cool down?'.
But, if do not define 'cool down' with an non-zero temperature differential value, then it is going to take forever.
RE: how to calculate time to cool an insulated tank
TTFN
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RE: how to calculate time to cool an insulated tank
the specific heat (kj/kg/degC) multiplied with the temperature differential (degC) multiplied with content tank (kg) gives you required heat.
required cooling capacity (kW)=required heat multiplied with time (sec)
RE: how to calculate time to cool an insulated tank
Good luck,
Latexman
RE: how to calculate time to cool an insulated tank
The key assumption is that the insulation is high enough that the cooling process always looks like steady state, i.e., the "stuff" inside the tank is roughly in thermal equilibrium at all times, in which case, the cooling time is as you've indicated.
Otherwise, the OP needs to consider the convection and conduction of his "stuff" as part of a transient cooling problem
TTFN
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RE: how to calculate time to cool an insulated tank
*Although the original poster gave no clues as to gender, the male pronoun is used as engineering as a profession is weighted more heavily towards males than females.***
*or she, of course.
***which just goes to show that we shouldn't make assumptions when there isn't information available, such as in the original poster's thread.
Patricia Lougheed
******
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