The cooling water thermodynamic analysis ??
The cooling water thermodynamic analysis ??
(OP)
the cooling water thermodynamic analysis used for cooling water chillers is
1TR=3.5KW= m CPw (twi-two)
m= 3.5 /(4.18 x (32-37))
= 0.167 kg/s
volume flow rate = 2.65 gpm
is that right?
cause i know that as a rule of thumb that 1 TR needs 3 gpm cooling water
1TR=3.5KW= m CPw (twi-two)
m= 3.5 /(4.18 x (32-37))
= 0.167 kg/s
volume flow rate = 2.65 gpm
is that right?
cause i know that as a rule of thumb that 1 TR needs 3 gpm cooling water





RE: The cooling water thermodynamic analysis ??
GPM (for the evaporator) = (tons x 24)/delta T
GPM (for the condenser) = (tons x 30)/delta T
So, the 3 gpm/ton you're thinking of applies to the condenser water (e.g., cooling tower water) with a 10 deg delta T. For the chilled water at 10 deg delta T it would be 2.4 gpm/ton.
RE: The cooling water thermodynamic analysis ??
say cooling load =600 TR then the condenser load = 702 TR
then the cooling tower flow rate = 2106 gpm right?
but if i had a chiller the water temprature difference = 16F
then the how much the condenser cooling water flow rate in that case?
RE: The cooling water thermodynamic analysis ??
The "rules of thumb" equations I posted before mean that the gpm required for the condenser is "typically" about 1.25 times more than that required for the evaporator. This number, similar to your 1.17, is presumably a ratio of condenser to evaporator heat rate. The actual factor will depend on the specific refrigerant, operating refrigerant condensing and evaportating temperatures, subcooling and superheat degrees, and compressor efficiency.
Assuming your 1.17 is the real number for your specific application, I would think the gpm for condenser water cooling would just be 1.17 times the gpm you get for chilled water flow rate.
In your example, if you're using the "rules of thumb" approach, you wouldn't multiply the tonnage by 1.17 and then use the 3 gpm/ton rule of thumb because that would be like multiplying by 1.17 and again by 1.25 or effectively multiplying by 1.46. If you want to use the 3 gpm/ton as an estimation, do it based on the 600 tons which would make your cooling tower flow rate 1800 gpm (@ 10 deg F), not 2106 gpm.
On the chilled water side, if you know you have a temp difference of 16 deg F, the flow rate would be (600 x 24)/16 = 900 gpm.
I assume your driving at "can we now take the 900 gpm and multiply by 1.25 to get 1125 gpm (or 1.17 to get 1053 gpm) condenser water flow (vs. the 1800 gpm)?" I don't think you can reduce your condenser water flow rate accordingly just because the chilled water flow rate is light (i.e, high delta T), because from a practical perspective, you won't be able to get a 16 deg F delta T at the cooling tower. Maybe someone else can weigh in on this last part...