Material pickup rate
Material pickup rate
(OP)
I think I'm missing something very simple but I'm stumped.
Here's my problem.
I have a material that weighs 100# pre cubic foot.
I have a conveying velocity of 7000 fpm and a total CFM of 150.
The Cu. Ft. of air per pond of material is roughly 35.
Based off these numbers I'm trying to figure what my flow rate is. It's seems as simple as taking the total cfm and dividing it by the required per pound giving me the rate the material is picked up.... 2.857#/min....
Is this correct or am I missing something?
Here's my problem.
I have a material that weighs 100# pre cubic foot.
I have a conveying velocity of 7000 fpm and a total CFM of 150.
The Cu. Ft. of air per pond of material is roughly 35.
Based off these numbers I'm trying to figure what my flow rate is. It's seems as simple as taking the total cfm and dividing it by the required per pound giving me the rate the material is picked up.... 2.857#/min....
Is this correct or am I missing something?





RE: Material pickup rate
RE: Material pickup rate
Thanks for your reply. I didn't word my post properly, well left out what I was looking to accomplish. Vacuum application.
I'm looking for the rate the material will be picked up per min lets say. My vacuum can handle 150cfm @ 7000fpm thru a 2" line. My material is 100# per cubic foot. I know the vac can pick up the material, just not the rate it will pick it up.
RE: Material pickup rate
35[cu.ft(air)/lb(material)]*100lb/cu.ft(material)/150cfm(total flow rate) ?
RE: Material pickup rate
150 CFM (air)/[35 cf(air)/lb(material)* 100 lb/Cu.Ft (material)] = 0.043 CFM (material)
RE: Material pickup rate
.043 cfm (material) seems really low. That means it would take nearly 3 hours to fill a 55 gallon drum.
RE: Material pickup rate
So 1 Cu.Ft of air can handle 0.01/35 =0.000286 Cu.Ft of material.
Being your air flow rate 150 CFM you can handle 0.000286*150=0.043 CFM of material.
RE: Material pickup rate
0.043*100 = 4.3 lb/min (material)