5 Aug 09 20:09
I have a working knowledge of geometry, algebra, and trigonometry but absolutely nothing about calculus.
Usually, when using metrics, I convert to feet, gallons, etc to be comfortable because this "SI" is almost baffling if it were not for a couple of conversion tables found on the Internet.
I need to calculate the Theoretical Horse Power at the horizontal shaft axis of a waterwheel being propelled by the flowing force of river water against the paddles of the waterwheel.
The animated image below is supposed to represent a Elevation view of a waterwheel in flowing water.
F = MA2 ÷ 2
F = power in ft-lb/sec
M = moving volume in lb/ft 3 ÷ 32.2 lb/slug
A = flow rate in ft/sec
F ft-lb/sec X 60 sec/min = F ft-lb/min
Theoretical Power (hp) = ( F ft-lb/min X rpm ) ÷ Factor 5252
Is my understanding of the Formula logical?
Ignoring wind, water surface ripples, impure water, temperature, and mechanical efficiency, I calculated a 12 ft. diameter waterwheel with 3 ft wide paddles, in a river flowing at a rate of 6 ft per second, will develop a 68.5 Theoretical Horse Power at the waterwheel axis shaft rotating at 9.55 rpm.
At 74th year working on IR-One2 - - UHK PhD - - -