pressure drop through a reducer
pressure drop through a reducer
(OP)
would like to know how to compute the pressure drop through a reducer from 20 inches to 12 inches if the inlet of the reducer has 195 centrigrade 77t/hr of crude oil column overhead vapour





RE: pressure drop through a reducer
In the reduction mode Hooper's equation is
K = (0.1 + 50/Re)( (D/d)^4 - 1 )
where
Re is based on inlet (large) diameter
D is inlet (large) diameter
d is small (outlet) diameter
A conical tapered reducer would give a higher K value than this.
Katmar Software
Engineering & Risk Analysis Software
http://katmarsoftware.com
RE: pressure drop through a reducer
RE: pressure drop through a reducer
for now let me use Katmars formula but generally speeking it seems its its difficult to calculate