API 650 Section 5.11.2 (Wind Load Unanchored Tanks)
API 650 Section 5.11.2 (Wind Load Unanchored Tanks)
(OP)
Can some one please advise me as to how tb (required thickness of the bottom plate under shell that is used to resist wind overturning) is calculated in API 650 section 5.11.2.
Thanks
Thanks





RE: API 650 Section 5.11.2 (Wind Load Unanchored Tanks)
RE: API 650 Section 5.11.2 (Wind Load Unanchored Tanks)
RE: API 650 Section 5.11.2 (Wind Load Unanchored Tanks)
1) When calculating wl based on 59tb(FbyH)^.5 the units are N/m, I assume that this is multiplied by the tank circumference to get the liquid weight. Please confirm.
2) The wl calculation using 0.9HD yields a value that is about 50 times less than in (1) above and the units would be in m^2? Can anyone explain this for me please.
Thanks
RE: API 650 Section 5.11.2 (Wind Load Unanchored Tanks)
I'm struggeling with the same problem as you xema77.
1) yes indeed ,if you multiplie the tank circumference and wl, you get the liquid weight.
(I assume that because, in API 650 edition 10 ad4,in formula E-23, wa is also computed for the tank circumference)
2) did you have already found an answer on this question?
RE: API 650 Section 5.11.2 (Wind Load Unanchored Tanks)
RE: API 650 Section 5.11.2 (Wind Load Unanchored Tanks)
RE: API 650 Section 5.11.2 (Wind Load Unanchored Tanks)
RE: API 650 Section 5.11.2 (Wind Load Unanchored Tanks)