Peripheral thrust formula for pyramid.
Peripheral thrust formula for pyramid.
(OP)
Anyone has this book "Design of pyramid" by Terrington John Stanley.
It has some formulae for peripheral thrust. Any guidance will be appreciated.
Thanks to all.
It has some formulae for peripheral thrust. Any guidance will be appreciated.
Thanks to all.






RE: Peripheral thrust formula for pyramid.
Amazon.co.uk
[United Kingdom] Publisher: Concrete Publications, 1939
Used, very good, Usually dispatched within 1-2 business days $112.55
RE: Peripheral thrust formula for pyramid.
Do you have a specific query regarding pyramids, we are much more helpful and responsive to those.
This seems to be very basic first principles type engineering.
RE: Peripheral thrust formula for pyramid.
the horizontally pushing force at the base
Push Hor = h·dens/ tan (alfa)
If h=140 m, dens=2.3 tonne/m3 alfa=55º
Push Hor = 225.45 tonne/m2 = 22.5 kgf/cm2 = 320 psi = 0.32 ksi.
Hope I have not erred in the trigonometry.
RE: Peripheral thrust formula for pyramid.
Weight=dens·section·sloped length=dens·dw·dt·h/tan(alfa)
Tangential thrust=Weight·sin(alfa)=dens·dw·dt·h·cos(alfa)
Horizontal push = Tangential thrust·cos(alfa)=
dens·dw·dt·h·(cos(alfa))^2
Horizontal pressure = Horizontal push / Vertical Area =
Horizontal push /(dw·dt/sin(alfa))=
dens·h·sin(alfa)·(cos(alfa))^2
hence for the example
2.3·140·sin(55)·(cos(55))^2=86.77 tonne/m2=8.67 kgf/cm2=
122 psi = 0.12 ksi
That sounds more reasonable; the other value seemed to high to me, so I reviewed the trigonometry.