CSYS name should be the Part Name
CSYS name should be the Part Name
(OP)
I'm required to create a "start part", such that it should convert the "default CSYS'S name" to the part name, i.e., if the user creates a new part using the start part, the name of the "default CSYS" and part should be same.
Please suggest a method for this.
Thanks in advance for the replies.
Please suggest a method for this.
Thanks in advance for the replies.





RE: CSYS name should be the Part Name
1. create a parameter called csys_name
2. create a relation that reads csys_name=&model_name
3. create a relation that then ties csys_name to your csys
you'll need to mess around with it to get it to work
RE: CSYS name should be the Part Name
RE: CSYS name should be the Part Name
mname=rel_model_name
then create a note
text being;
{0:\}{1:&MNAME}
and attach that to the csys, which then gives me the model name as a note by the csys.
What would be the syntax to change the actual name of the csys?
I tried a number of variations with ;
fid_7 being my csys
name:fid_7 =mname
label:fid_7 =mname
fea_name:fid_7 =mname
all give me errors in rel.editor, but
I can reverse the order and create those feature parameters?
what would be the value for ????:fid_7
RE: CSYS name should be the Part Name
Appreciate if anyone could post a solution for this.
Thanks.
RE: CSYS name should be the Part Name
That's the best solution I have. I also can get the path name in there if I want. that's why the slash here;
{0:\}{1:&MNAME}
RE: CSYS name should be the Part Name
File > Rename
"pause"
Please select all and CTRL+C to copy and hit continue
Select COORD SYSTEM
F2 rename
"pause"
Paste part name as CSYS name
END MAPKEY
Michael
RE: CSYS name should be the Part Name