Closed loop - Gauge pressure vs fill volume
Closed loop - Gauge pressure vs fill volume
(OP)
Hi all, please help with the below question.
Consider a 300ft , Dia = 1-inch ID copper pipe closed loop system laid horizontally i.e., elevation = 0.
To fill the system fully with water we would need:
System Volume= (3.14/4)x(D^2)x 300' = 1.636 ft^3 = 12.24gal
A pressure gauge in the loop will be reading 0 psig(atm pressure) when the above system is filled with 12.24gal.
How much more volume is to be introduced into the system to raise the fill pressure to, say 10 psig?
In other words, what is the relation between volume of fluid in a closed loop and static fill pressure in a system?
Thanks in advance.
Consider a 300ft , Dia = 1-inch ID copper pipe closed loop system laid horizontally i.e., elevation = 0.
To fill the system fully with water we would need:
System Volume= (3.14/4)x(D^2)x 300' = 1.636 ft^3 = 12.24gal
A pressure gauge in the loop will be reading 0 psig(atm pressure) when the above system is filled with 12.24gal.
How much more volume is to be introduced into the system to raise the fill pressure to, say 10 psig?
In other words, what is the relation between volume of fluid in a closed loop and static fill pressure in a system?
Thanks in advance.





RE: Closed loop - Gauge pressure vs fill volume
RE: Closed loop - Gauge pressure vs fill volume
See this link,
http://w
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"Pumping accounts for 20% of the world's energy used by electric motors and 25-50% of the total electrical energy usage in certain industrial facilities."-DOE statistic (Note: Make that 99% for pipeline companies) http://virtualpipeline.spaces.live.com/
RE: Closed loop - Gauge pressure vs fill volume
i would test this small volume with a hand pump instead of a powered pump.
this could overpressure in a real hurry
RE: Closed loop - Gauge pressure vs fill volume
Thanks very much BigInch and vesselfab for the help.