"h" value in calculating HSS nominal shear strength?
"h" value in calculating HSS nominal shear strength?
(OP)
I am looking at AISC-13th 16.1-68 sect.G4, it says in calculating rectangular HSS nominal shear strength, the area Aw=2ht, where h shall be taken as the corresponding outside dimension minus three time the thickness.
Now look at AISC Example G.4 (Example page G-8), "h" is taken as:
h=d-2*(3*tw)=6-2(3)0.349)=3.91 in. (note: there is a "2" multiplies 3 times of the thickness)
Look at another AISC Example H.5c(page H-15), "h" is taken as:
h=d-3*tw=6-3(0.233)=5.3 in. (note: there is just "1" multiplies 3 times of the thickness)
These two examples, which one is correct, which one is wrong?
Thanks.
Now look at AISC Example G.4 (Example page G-8), "h" is taken as:
h=d-2*(3*tw)=6-2(3)0.349)=3.91 in. (note: there is a "2" multiplies 3 times of the thickness)
Look at another AISC Example H.5c(page H-15), "h" is taken as:
h=d-3*tw=6-3(0.233)=5.3 in. (note: there is just "1" multiplies 3 times of the thickness)
These two examples, which one is correct, which one is wrong?
Thanks.






RE: "h" value in calculating HSS nominal shear strength?
RE: "h" value in calculating HSS nominal shear strength?
Page 1-5 says that this radius is assumed to be 1.5t, but that the tolerances of ASTM A500 allow it to be as much as 3t. Perhaps that is why the example on page G-8 took off 3t twice, using the upper bound for the radius. This would appear to be conservative and unnecessary, though, since section B4.2 says to use 1.5t.
If I were doing one of these calculations, I would follow H-15.
RE: "h" value in calculating HSS nominal shear strength?
One more question to ask: if this kind of question showed up in SE I exam, which answer you think NCEES will accept as a correct answer?
Thank you very much.
RE: "h" value in calculating HSS nominal shear strength?
If it's multiple choice, though, just hope both answers aren't there!