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Joint Loads

Joint Loads

Joint Loads

(OP)
Hello All,

I am using FEMAP NX NASTRAN 9.3. Currently I am working on finite modelling of class divider and it is with dog house. I was wondering if anyone of you know how to get the joint loads between partition and doghouse? Please see attached for the picture and clarification of my problem.

Thanks,
Audacious

RE: Joint Loads

does the divider attach directly to the floor ?

i assume the divider is existing (= already approved).

if so, i'd say that the divider can happily continue doing it's job, that the "doghouse" only makes it stronger, and the "doghouse" is secondary to the divider ... as the divider loads up (say under de-compression), it May drive load into the doghouse, which May yield and so become soft and the loadpath represented by the doghouse would "disappear" and the divider structure would carry on supporting load, as though the doghouse wasn't there.

then what loads the doghouse ?  maybe a pax putting their feet up on it (inspite of your placards saying "don't").  maybe a load of 200 lbs in any direction would be reasonably conservative.

but maybe in adding the dogouse, you've also cut away the divider ?  in which case everything is different.
 

RE: Joint Loads

(OP)
Thanks a lot for your reply. Divider and doghouse is one assembly there are two lower attachments through divider and two through doghouse. What I am intersted in is how much the loading will be on the joints between doghouse and divider due to 9G FWD loading condition etc. Please see attached for another view.

RE: Joint Loads

since this is a model, why don't you let the FEM tell you ?  apply your load, and see what the reactions are.  i would caution that full fixing the 4 points is going to create redundant moments and couples in your reactions. better i think just to pin the 4 points.

if you want to do a hand calc, consider the divider as a proped cantilever.

worry about possible decompression loads ... is there a companion divider on the other side of the aisle ? if there isn't, then there probably isn't a problem.

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