Heat Exchanger Pressure Drop
Heat Exchanger Pressure Drop
(OP)
We have a tube and shell heat exchanger that is made in-house.
It has one face that is ~45" x ~30" with 150 2" pipes open to the gas stream. The gas goes through some equipment where it is cooled and then crosses back over so it perpendicular to the flow of the first pass. The flow on the second pass is across the path of the 2" pipes. The second opening is ~45" x 24" wide.
I'm trying to get some rough numbers for pressure drop. I have a feeling that the number we initially expected are way too low.
It has one face that is ~45" x ~30" with 150 2" pipes open to the gas stream. The gas goes through some equipment where it is cooled and then crosses back over so it perpendicular to the flow of the first pass. The flow on the second pass is across the path of the 2" pipes. The second opening is ~45" x 24" wide.
I'm trying to get some rough numbers for pressure drop. I have a feeling that the number we initially expected are way too low.





RE: Heat Exchanger Pressure Drop
RE: Heat Exchanger Pressure Drop
RE: Heat Exchanger Pressure Drop
Quoting the equation for your reference.
dP = fG2Ln/(5.22x1010Dsφt)
f is dimensional friction factor, sq.ft/sq.in (I have attached the graph here)
G is mass velocity in lb/hr sq.ft
L is length of tube path in ft
n is no. of tube passes
dP is pressure drop in psi
φ is a factor (of viscosities) to compensate the diffference in heat transfer coefficients at wall temperature and bulk temperature (I think you can omit this as the viscosity change will be not significant for gases)
s is specific gravity (Kern might have considered s value against water)
PS: 1. Heat Exchanger Design by Sadic Kakac may be of help to you. 2. You may get better response from Heat Transfer or Chemical Fora
RE: Heat Exchanger Pressure Drop
Thanks again.