torsional rigidity of sway bar or torque tube
torsional rigidity of sway bar or torque tube
(OP)
The equation I found for this is assuming the use of mild steel and is as follows.
R= (5x10^6 x D^4)/(.4244LA^2 +.2264B^3)
D=diameter
A=effective lever arm length
B=lever arm length (same as above no? unless arm is at an angle)
L=length of bar or tube or whatever
R=roll bar rate
Now I am curious if anyone else is familiar with this equation and if it is in Ib/ft per degree or what?
R= (5x10^6 x D^4)/(.4244LA^2 +.2264B^3)
D=diameter
A=effective lever arm length
B=lever arm length (same as above no? unless arm is at an angle)
L=length of bar or tube or whatever
R=roll bar rate
Now I am curious if anyone else is familiar with this equation and if it is in Ib/ft per degree or what?





RE: torsional rigidity of sway bar or torque tube
Two structural beam formulas for displacement have been merged into one for simplicity. Several smaller terms have been assumed negligible. For a front sta-bar, A usually does not = B due to the space requirement for steering the wheels.
Do a dimensional analysis of the equation and see what you end up with for units once you do some cancelling. The 5E6 in the numerator is in units of psi if you're working in inches/lbs/seconds.
Norm
RE: torsional rigidity of sway bar or torque tube
IIRC, the 5E6 is 500,000 or 5E5 in the book. 0.5E6 (?)
N
RE: torsional rigidity of sway bar or torque tube