Concentrated loads on steel plate
Concentrated loads on steel plate
(OP)
I am designing an outrigger which will consist of steel beams at 30" oc with a 1/4" steel plate continuous over several spans. The concentrated load will be from a pallet jack with a very small wheel. My question is how much load distribution could I expect in the steel plate parallel to the steel beam supports. What would be a reasonable approach (not finite element).
Thanks
Thanks






RE: Concentrated loads on steel plate
Other than FEA or YLA, your guess is about as good as anybody's as to an equivalent one-way span.
The thing I dislike soooo much about coming up with a width by judgment is that the strength can be made just about anything you want. Also, without having done a bunch of YLA or FEA, I don't know where the judgment comes from.
RE: Concentrated loads on steel plate
I am not at my office right now so I do not have my references but will send info. as soon as I can.
RE: Concentrated loads on steel plate
In the Australian code for concrete design (AS 3600), the effective width of a one-way slab, deemed to resist moments caused by a concentrated load, not located near an unsupported edge, is given by the following equation:
bef = b + 2.4*a*[1-(a/L)]
where:
- bef is the effective width
- b is the load width
- a is the perpendicular distance from the nearer support to the section under consideration
- L is the clear span of the slab
If the load width, b, is conservatively assumed to be 0 and the concentrated load is at midspan, then the effective width of the slab, bef, is 60% of the clear span, L.
RE: Concentrated loads on steel plate
RE: Concentrated loads on steel plate
How much of the width do you need to work for the load to be acceptable? How will you attach the place to the beams?
Keep discussing. I have a plate loading reference somewhere if I can think of it, I will post.
Daniel Toon
RE: Concentrated loads on steel plate
Roark does give a formula for stress on a rectangular plate (of different aspect ratios) for one concentrated load of a particular diameter.
If you have the possibility of two loaded wheels with the wheel spacing less than about 0.6 x clear span (as mentioned by dbuzz), you may need to take into account overlapping stresses by reducing the effective width to 0.3 x clear span + 1/2 wheel spacing. For wheels with small contact areas such as you have, I would ignore any affect that may have on increasing the effective width.
RE: Concentrated loads on steel plate
Is there any chance you may provide Roark's formula?
I can't find it in any of my reference material.
Also, How can I find the British standard; I have done a search on google with no luck.
Thanks
RE: Concentrated loads on steel plate
There is a table for this so it is not really possible to give you a formula.
csd
RE: Concentrated loads on steel plate
RE: Concentrated loads on steel plate
I will purchase the text as suggested and possibly the British standard also.
Thanks again to everyone.
RE: Concentrated loads on steel plate
csd
RE: Concentrated loads on steel plate