HYDRO MECHANICAL SHEAR
HYDRO MECHANICAL SHEAR
(OP)
If anybody please help me telling how to determine the Shear Load (if its the right term) required to cut a strip 0.53 inch thick and has a yield strength of 80,000 psi. Im just confused as others use the shear strength and others use the yield strength when using F=A x Ss. The blade angle is 2.2 degrees.
Thanks
Thanks





RE: HYDRO MECHANICAL SHEAR
You need to provide the width of the strip in addition to the thickness.
You need to use the shear strength of the material, not the yield strength. If you don't know the shear strength, you can estimate it as ~ 0.6 · ultimate tensile strength.
Blade angle is irrelevant for macro-scale force calculation.
Regards,
Cory
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RE: HYDRO MECHANICAL SHEAR
The width of the material is 92 inches, the blade angle as i understand will also affect the Area and the force eventually.
And what do you think would be the proper penetration to fracture?
RE: HYDRO MECHANICAL SHEAR
Assuming the material ultimate tensile strength is 100 ksi (should be in the ballpark for 80 ksi yield), then the shear strength is ~ 60 ksi. Then the force would be 92 in · 0.53 in · 60 ksi = 2.9 million pounds-force.
That is a stout shear you have in mind.
Regards,
Cory
Please see FAQ731-376: Eng-Tips.com Forum Policies for tips on how to make the best use of Eng-Tips Fora.
RE: HYDRO MECHANICAL SHEAR
Your assuming the whole thing gets chomped at once. I would think for this application that the shear blade would be angled and progressively shear the material.
-b
RE: HYDRO MECHANICAL SHEAR
Mike Halloran
Pembroke Pines, FL, USA
RE: HYDRO MECHANICAL SHEAR