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ASCE7 Ice Loads

ASCE7 Ice Loads

ASCE7 Ice Loads

(OP)
I am designing the foundation for a minor tower.  The specifications included design of ice loads from ASCE7-02.  When I use eqn 10-1 to calculate the area it seems excessive.  It takes a length times a width (a rectangle) and then multiplies it by pi.  I understand pi*D^2/4 as an area but the division by 4 is missing.  I checked ASCE7-05 but the eqn is the same.  I do not have a copy of ANSI/EIA/TIA222.  Does it have a comparable eqn?  ASCE7 already doubles the ice thickness to go from a "radius" to "diameter" type calculation.  Thanks

RE: ASCE7 Ice Loads

The wind area is the projected area facin wind.(not the cross vsection)

RE: ASCE7 Ice Loads

It seems that ice would form over the surface area, not the cross sectional area.  To get surface area, I would expect you to take length times width times 4 for a rectangular section.  Pi is less than 4.  Does it seem so unreasonable then?

RE: ASCE7 Ice Loads

BTW an 800' tower recently came down due to combined high wind and ice.This belonged to www.wnep.com in Scranton ,see photos on the website.

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