A bit of mathamatics
A bit of mathamatics
(OP)
Is there any method to go for solving equations below
except for using sin[square]a + cos[square]a = 1
any short tricky method
6.58*cos(a) = 3.81 + .058*B
6.58sin(a) = .0056*B
where a is angle in degree B is a numeric value
In early need of answer
thanking you
except for using sin[square]a + cos[square]a = 1
any short tricky method
6.58*cos(a) = 3.81 + .058*B
6.58sin(a) = .0056*B
where a is angle in degree B is a numeric value
In early need of answer
thanking you





RE: A bit of mathamatics
Nigel Waterhouse
n_a_waterhouse@hotmail.com
A licensed aircraft mechanic and graduate engineer. Attended university in England and graduated in 1996. Currenty,living in British Columbia,Canada, working as a design engineer responsible for aircraft mods and STC's.
RE: A bit of mathamatics
Good luck.
RE: A bit of mathamatics
RE: A bit of mathamatics
RE: A bit of mathamatics
a. Pencil and paper with some numerical method for the solution of a system of nonlinear transcendental equations. Modern software often use iteration methods since the computer hardware processes them easily.
b. Graphical methods are good but not much accurate. Incidentally, what kind of accuracy do you need for that solution?
c. The easiest way nowadays is the computer math software. I suggest that you type at your search engine "math software" and some reasonably good packages will appear on the screen. This is what I did long time ago when such packages were inexpensive.
d. I used that software and I got the following results:
a=0.04058 in radians
b=47.66524 in per unit
in the interval a<=3 radians and b>0 in per unit