Metric Gear sources
Metric Gear sources
(OP)
Hey everyone,
I'm doing up a drawing set for a machine that came into our shop, but I don't know where to find information on the gearing.
I know they are metric gears, but the only information I have on them are: the gear has 72 teeth and an approximate outside diameter of about 14-1/2", and the pinion has 18 teeth and an OD of about 4". I'd like to keep these dimensions somewhat similar, but the dimension I need is that the center to center distance of the gears has to be 225mm.
If it matters both of the gears have hubs on each side and keyways, but we can probably put that in after. Thanks for your help.
I'm doing up a drawing set for a machine that came into our shop, but I don't know where to find information on the gearing.
I know they are metric gears, but the only information I have on them are: the gear has 72 teeth and an approximate outside diameter of about 14-1/2", and the pinion has 18 teeth and an OD of about 4". I'd like to keep these dimensions somewhat similar, but the dimension I need is that the center to center distance of the gears has to be 225mm.
If it matters both of the gears have hubs on each side and keyways, but we can probably put that in after. Thanks for your help.





RE: Metric Gear sources
http://www.hpcgears.com/
If you can't find it there then try Misumi
http://www.misumi-europe.com/eucatalogue/25.html
Kevin Hammond
Mechanical Design Engineer
Derbyshire, UK
RE: Metric Gear sources
Try this company in Italy - they do great work and will probably make one-offs.
http://www.cmr.it
RE: Metric Gear sources
The od of the 72 tooth gear would be
72 times 5 plus 10 equals 370mm or 14.567 inches.
The od of the 18 tooth gear would be
18 times 5 plus 10 equals 100mm or 3.937 inches.
These would operate on a 225mm Center Distance.
RE: Metric Gear sources
Center distance = (pitch dia1+pitch dia2)/2
Therefore:
Module = center distance/((no of teeth1+no of teeth2)/2)
module = 225/((78+18)/2) = 5
as already mentioned dimjim