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Thermal expansion

Thermal expansion

Thermal expansion

(OP)
Hi Guys,

In my current project for Indirect heaters, I would like to calculate the Thermal expansion of the tubes of size 30" OD with the design temperature of 300 Deg F which runs for 52' in length. I took the linear co-efficient of expansion as 8.30E-05 for carbon steel pipes and was able to calculate the expansion in length wise. But I need the expansion in Diameter wise. That is how much will a 30"OD expand?

Need all your expertise in this.
Thanks in advance,
Aravind Sujay

RE: Thermal expansion

Hi AravindSujay

Just treat the 30" o.d. as you did the length

30*8.05*10^-5*temp diff

regards

desertfox

RE: Thermal expansion


It appears that the thermal linear expansion coefficient for steel is in error. It should be 8.3×10-6/oF. Kindly confirm.

RE: Thermal expansion

Hi 25362

Yes it should be 10^-6 I agree.
When I look the value up it says 6.3* 10^-5 however I wonder what the value is at 300F as the figure I have here is at room temp.

regards

desertfox

RE: Thermal expansion

Aravind,

Are you trying to calculate expansion of this heater for a stress analysis of piping that is attached ?

-MJC

  

RE: Thermal expansion


Perry (6th Ed.) gives for steel's linear thermal expansion, the following equation:

Lt = Lo (1 + αt + βt2)

Lt is the length at t in oC
Lo is the length at 0oC
α = 0.1118×10-4
β = 0.0053×10-6

The equation is applicable over the temperature range 0oC→750oC.

RE: Thermal expansion

(OP)
Hi all, I used 30*8.05*10^-6*temp diff.
Thanks for all your answers.

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